Given:

P=0.03=3%

Given claim : Die favors 6(when no favoring, we have 1 chance in 6 to roll a 6)

The claim is either the null hypothesis or the alternative hypothesis. The null hypothesis states that the population proportion is equal to the value mentioned in the claim. If the null hypothesis is the claim, then the alternative hypothesis states the opposite of the null hypothesis.

\(\displaystyle{H}_{{0}}:{p}={\frac{{{1}}}{{{6}}}}\)

\(\displaystyle{H}_{{a}}:{p}{>}{\frac{{{1}}}{{{6}}}}\)

The P-value is the probability of obtaining the value of the test statistic, or a value more extreme, when the null hypothesis is true.

In this case, the P-value then means : there is a chance 3% of obtaining a sample proportion higher than \(\displaystyle\frac{1}{{6}}\), when the die is not loaded or fair.

Result: (c) is correct